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In the continue Loop -
i = 0
while True:
i = i +1
if i == 2:
print("Skipping 2")
continue
if i == 5:
print("Breaking")
break
print(i)
print("Finished")
It shows the output being
"1
Skipping 2
3
4
Breaking
Finished"
Why are the last three lines not
"Breaking
5
Finished"
Where it shows print(i) after break?
1 Vote
3 Answerscan someone please explain why this code keeps telling me complication error instead of outputting the value of speed.
#include <iostream>
using namespace std;
class myClass {
public:
void setcarspeed (int a){
speed=a;
}
int getcarspeed(){
return speed;
}
private:
int speed;
};
int main() {
myClass obj;
obj.setcarspeed (40);
cout<<obj.getcarspeed ;
return 0;
}
2 Votes
3 Answersis the javascript used for server side same as that of client side javascript??
i mean is syntax exactly same.
i want to know difference. there must be some.
i know node.js is used in backend and jquery,angular in front end, but overall they r javascript so why should it matter???.
thanks in advance
2 Votes
3 AnswersWhile prototyping friend functions in a class is it necessary to always pass the address of the object as parameter?If so why is it that we have to pass address as parameter..In programs involving compositions we never used addresses...Why is the need for address of the objects while using friend?
4 Votes
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