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C++ task about
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1 AnswerMatt reaches the final round of a treasure hunt. In this, he finds that as he proceeds there are flags with the number written on them at different positions. The difference between two consecutive flags can be either a or b. If he finds the number on the first flag is 0. Given three integer, first one is number of flags present, second is a and third is b. then return all the possible values for last flag for each test case.
hunt({3 1 2}) = {2 3 4}
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1 AnswerCan someone explain this code to me....
class ReverseNumberDemo
{ public static void main(String args[]) {
int num=123456789;
int reversenum =0;
while( num != 0 ) {
reversenum = reversenum * 10;
reversenum = reversenum + num%10;
num = num/10; }
System.out.println("Reverse of specified number is: "+reversenum);
}
}
the thing I don't get is the reversenum part......isn't reversenum=0 so wouldn't reversenum*10=0
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