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[ASSIGNMENT] Reverse String๐ฉ๐ฉ
Task: take input from user. Then, reverse it using any method. Example: input: solo output: olos input: say output: yas You can use any language to perform this task. I already submitted this challenge to Lesson Factory. https://code.sololearn.com/cpAv2CZejx67/?ref=app
27 Answers
+ 24
https://code.sololearn.com/c3luPGo2uDq3/?ref=app
+ 24
<!-- My try in PHP โ๏ธ๐ ๐
Unfortunately can't take user input
(1 Liner) ๐๐๐ -->
<?php
$str = "solo";
echo "Input : $str<br>"."Output: ".strrev($str);
?>
+ 23
Muhammad Khairul Amirin Bin Yaacob
๐๐๐๐Thank you very much, ๐๐ค
I'm really honored, surprised and delighted!! ๐๐๐๐ค
I'm glad you like my answer and I'm thrilled that you have chosen my answer
for The Best! โบ๐๐
Thanks a lot ๐๐
+ 11
Python -
print(input()[::-1])
JS -
document.write(prompt().split("").reverse().join(""))
+ 9
Three line in ruby:
https://code.sololearn.com/cgJlrvTdTomv/?ref=app
+ 8
one liner in js
console.log(prompt("Enter any word").split("").reverse().join(""));
+ 7
oneliner in python
print(input()[::-1])
https://code.sololearn.com/cz0c0WkSPldd/?ref=app
+ 7
Nice Game ;-)
Functional programming!
Use spread operator ES6
function reverseString(s){ return [...s].reverse().join("");}
Use arrow functions and reduce in ES6
function reverseString(s){ return [...s].reduceRight( (prev, curr) => prev + curr );}
Use ES6 Ternery operator and recursion
function reverseString(s){return (s === '') ? '' : reverseString(s.substr(1)) + s.charAt(0);
}
+ 7
Very simple code in Ruby
https://code.sololearn.com/cS6sl3iQPJqz/?ref=app
+ 6
There is more than one way to do this:
https://code.sololearn.com/c0NFcB1dD5Yu/?ref=app
+ 6
Here it is in JS
https://code.sololearn.com/W5twGmh0scL2/?ref=app
+ 5
+ 5
Just use string method reverse().
+ 4
In C++, just use std::reverse to do the work for you.
+ 4
My try in Java.
https://code.sololearn.com/c2MRxBHAKAbX/?ref=app
+ 4
one liner in python:
print (input ()[::-1])
+ 4
mitali jadhavrao In JS.
+ 3
python code for reverse of string
https://code.sololearn.com/cN964QIsKZUH/?ref=app