+ 18

How can I find the sum of first 5 numbers of an array using for each statement (eg: int num[ ]={1,2,3,4,5,6,7,8,9,10})

30th Jun 2018, 2:15 PM
thealoneprogrammer
thealoneprogrammer - avatar
31 Answers
+ 28
// using for-each loop int count = 0; int sum = 0; for (int n : num) { sum += n; count++; if (count == 5) break; }
30th Jun 2018, 2:29 PM
Phurinat Puekkham
Phurinat Puekkham - avatar
+ 10
yes thank you Phurinat Puekkham
30th Jun 2018, 2:36 PM
thealoneprogrammer
thealoneprogrammer - avatar
+ 9
Robert Atkins that solution holds in case of for loop I was talking about for each loop anyways thank you
30th Jun 2018, 3:28 PM
thealoneprogrammer
thealoneprogrammer - avatar
+ 9
thank you Hamid
2nd Jul 2018, 7:30 AM
thealoneprogrammer
thealoneprogrammer - avatar
+ 8
yes I agree with you Miqdad
1st Jul 2018, 2:46 PM
thealoneprogrammer
thealoneprogrammer - avatar
+ 6
>= actually not required once the count becomes 5, break will execute and it will come outof for-each loop. so, no further addition of array elements beyond fifth one.
1st Jul 2018, 1:05 PM
Miqdad
Miqdad - avatar
+ 5
you could act like so: https://code.sololearn.com/cijSO0YPJ02h/?ref=app Python wont give error even if elements are less than 5 .
2nd Jul 2018, 6:20 AM
Hamid
Hamid - avatar
+ 5
static int count = 0; int sum = 0; for ( int i : num ){ sum += I; if ( ++count == 5 ) break; }
4th Jul 2018, 7:48 PM
Oleksandr Chekalenko
Oleksandr Chekalenko - avatar
+ 3
This hopefully should help you: // using for-each loop int count = 0; int sum = 0; for (int n : num) { sum += n; count++; if (count == 5) break; }
30th Jun 2018, 8:52 PM
coolboy7
coolboy7 - avatar
+ 3
hello, 'for each' loops are not appropriate when you want to modify array but you can use 'break' keyword as you want to add only first five numbers.
1st Jul 2018, 12:09 PM
Tarika
Tarika - avatar
+ 3
Gajarajan, please check before u comment...
1st Jul 2018, 12:59 PM
Miqdad
Miqdad - avatar
+ 3
sorry i'm wrong i just confused with that function of break and continue
1st Jul 2018, 1:02 PM
Gajarajan K
Gajarajan K - avatar
+ 3
may suggest an easier way of just putting the first 5 element of said given list in a variable of their own and using it as the counter in the for loop.
1st Jul 2018, 10:18 PM
David Masabo
David Masabo - avatar
+ 3
It was nothing. Happy Coding
2nd Jul 2018, 7:32 AM
Hamid
Hamid - avatar
+ 3
The problem requires a for-each loop, and no one suggested one. I find this strange. Wikipedia has a nice example. Using that and Phurinat's code, the proper solution can be worked out. Always pay attention to the requirements, especially on exams. P.S. My Java is rusty indeed. I assumed "each" should be present in the code, but I read online and it turned out I was wrong. 😝
2nd Jul 2018, 12:55 PM
Nicolae Crefelean
Nicolae Crefelean - avatar
+ 3
int ar[10] = {1,2,3,4,5,6,7,8,9,10}; int count=5; int sum; foreach(int num in ar) { if(ar.length<=5) sum = sum + num; } display sum
2nd Jul 2018, 12:58 PM
Raouf Yasin
Raouf Yasin - avatar
+ 2
final int SUMTIL= 5; int sum; for (int i = 0; i<SUMTIL;++i){ sum +=num[i]; } then you can change SUMTIL til you get what you need
30th Jun 2018, 3:11 PM
StealthyTaco
StealthyTaco - avatar
+ 2
Sujith D My apologies, sometimes it helps to understand what someone is asking lol. the only downside to a for each loop is, you cant use it to find what index you are at, so you could search to see if something was in your array, but you could not easily find what index the value was located at. just a tidbit for you.
1st Jul 2018, 9:44 AM
StealthyTaco
StealthyTaco - avatar
+ 2
//for-each loop int count = 0, sum = 0; for(int x : num){ sum+=x; if(++count==5) break; }
1st Jul 2018, 12:09 PM
Miqdad
Miqdad - avatar
+ 2
All answer are wrong because the author is asking for foreach loop
2nd Jul 2018, 12:54 PM
Raouf Yasin
Raouf Yasin - avatar