Help Please

Question

hi
pls how should i write this ?
import string

number = input("Please enter ur number:\n")
if number == string:
print("please enter a number")
break
else:
number = float(number)

if (number) < 50:
print(f"Your number {number} < 50")
if (number) > 50:
print(f"Your number {number} > 50")

error :
line 7
break
^
SyntaxError: 'break' outside loop

Answer 1

The break keyword is used in loops.
Remove the break keyword

Checking if the entered value is string or not won't work that way...

Try this 👇

try:

number = float(input("Please enter ur number:\n"))

if (number) < 50:
print(f"Your number {number} < 50")

if (number) > 50:
print(f"Your number {number} > 50")

except ValueError:

print("Please enter a number")

Answer 2

use quit() instead of break

Answer 3

✔✅Barry🔧 is there another way to write this easier?

Answer 4

If is not a loop statement hence there is no need of break (break is used to get out of loop)

 three basic types of control structures:

Sequential: default mode. Sequential execution of code statements (one line after another) -- like following a recipe

Selection: used for decisions, branching -- choosing between 2 or more alternative paths. In C++, these are the types of selection statements:
if
if/else
switch

Repetition: used for looping, i.e. repeating a piece of code multiple times in a row. In C++, there are three types of loops:
while
do/while
for

Here is my modified code... Hope it will help you

https://code.sololearn.com/crVtXIi3TyJs/?ref=app