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ceil without math

+9

Author: Tibor Santa

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# ceil without math
for x in (1.999, 2, 2.001, 2.5, 2.6, -1.1, -1, -0.9):
    r = int(x) if int(x) >= x else int(x+1)
    print(f'{x:5}{r:5}')

OUTPUT

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