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Fibonacci without recursion
+1
Author: Jan
Dark
Public
Save
PY
py
1
2
3
4
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7
8
def
fib
(
n
):
a
,
b =
0
,
1
for
c
in
range
(
1
,
n +
1
):
a
,
b = b
,
a + b
if
c == n
:
print
(
c
,
"-->"
,
a
)
fib
(
1000
)
Enter to Rename, Shift+Enter to Preview
OUTPUT