What's the answer for this code in c++ & c#and why?

Question

int a,b;
a=-5;
b=2;
if(a/b)
{cout<<"True";}
else
{cout<<"False";}

Answer 1

The answer must be False for both the languages. As anything other than 0 is true and 0 is False.
2/-5=-0.4
But since data type is int only 0 that is the integral part of the number will be stored. So
a/b = 0 i.e. false. So the else part gets executed to output false.

Answer 2

yes.
any number except 0
integer +ve or -ve
floating
double
all are true
except 0.

Answer 3

thanks for the help brother!

Answer 4

that means all the numbers except 0 are treated as true @David-Hesh Hochhauser

Answer 5

does it works for negative values too?

Answer 6

Megatron has it almost right. But his numbers are backwards. -5 / 2 as integer = -2. which is True because -2 is not 0. This is because of how numbers are stored in binary. All non-zero values (even negative ones) have at least one bit set in their binary representation. So any non-zero value, Int or float, is considered True. However, in C you can evaluate an integer by its individual bits.

For example: 3 && 4 = True and True = True
but single & is bitwise in binary
3 & 4 = 011 and 100 bit by bit = 000 = False