Plz explain me the below code ...plz....especially line 2 .....

Question

def apply_twice(func, arg):
return func(func(arg))

def add_five(x):
return x + 5

print(apply_twice(add_five, 10))

Answer 1

def apply_twice (func,arg):
return func(arg)
def add_five(x):
return x+5
print (apply_twice(add_five,10))

here in the second line I have just replaced by func(arg)....plz reply fast....plz explain in easy words...

Answer 2

Okay, think of it like this.

func = apply_twice()
arg = 10

^To better understand Line 2, just swap out func/arg with the above.

EXAMPLE:
return add_five(add_five(10))

^As you can see when you swap it out, you're calling the add_five function twice. The inner function argument is calling 'add_five' with the value of 10, and then the function returns the new value (10 + 5) of 15, which calls the function again with the new arg of 15. The function adds 5 again resulting in a value of 20.

Answer 3

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Answer 4

func(func(arg))
but what does this actually mean or do...