How does ths code work? (i didn't understand) explain line by line.....

Question

def fib(n):
a = 1
b = 1
while a<n:
result.append(a)
tmp_var = b
b = a+b
a = tmp_var
return result

print(fib(10))

Answer 1

This is Fibonacci series, means each number is equals to the sum of the two before him. a(n+2)=a(n+1)+a(n) if you know Math series's(Recursion). so it starts with 1(default value entered) and then its 1+0=1 and 1+1=2 and 1+2=3 and 2+3=5 and so goes on...
The codes works like this. result is probably a list which you're appending each time in the while loop(with a). then a Temp variable is equal to b. basically the a(n+1) in the math series example. then b gets a new value of a(which is a(n)+an(+1) which is b at that point of time. which means b is now a(n+2).
then a gets a new value which is a(n+1) which will be a(n) in the next time we run the while loop. The n variable in this function means: Until which value in the series should we get to. Meaning if we enter n as 10 we will get every value of the Fibonacci series until 10.

Answer 2

What is result?

Answer 3

I have redone your code, changed tmp_var to c because of reasons.
https://code.sololearn.com/cVX5e68ZL79e/#py

Answer 4

well it wont for two reasons because 1) the return function is one space ahead and 2) you need to define the variable result