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Pointer
int x = 5; int *p = &x; x = x + 4; x = *p + 4; *p = *p + 4; ââââââââââââ Why *p == x ?
1 Antwort
+ 1
cause *p access the value of x using address of x as it's value!
int x = 5; int *p = &x; x = x + 4; x = *p + 4; *p = *p + 4; ââââââââââââ Why *p == x ?