What you think about this?? Is it run successfully or not??if yes or no then why??lets clear basics😊😊

Question

#include <iostream>
using namespace std;
int main() {
void x=10;
cout<<x;
return 0;
}

https://code.sololearn.com/ccOe4o8nUhcx/?ref=app

Answer 1

why is anyone think that is this compile?

Answer 2

share what you think and why about this ??

Answer 3

@Deepak Gautam
😊😊🙄🙄
👌👌

Answer 4

@sayan chandra
😊😊

Answer 5

@Willz
it is not matter what you assign to x it is focused on void anyway thank you for your answer
😊😊👍

Answer 6

u can not declare a variable as void...

a variable must be of a legitimate type..
like int..float...double...char...or array type etc...

void is a return type
a return type goes only with a function...that has a possibility to return a value or charecter...or null..or an adress...or an array..or even the function itself...

so...
void x is an error..

Answer 7

void isn't a datatype. it's a function.[this part is wrong]

Answer 8

@sayan I wasn't referencing your answer. 🤔🖖

Answer 9

void can only work as a return type because some functions don't need to return anything. Storing a void or empty value doesn't make any sence.

Answer 10

wait brother...

i didnt say void is a data type..

i said void is a return type of a func.
its not a function

void means...
the function doesnt returns anything...

it suggests that only..

Answer 11

✌✌

Answer 12

The same thing.. but thanks

Answer 13

You’re literally allocating the value of x to 0 , thanks to the “void” return type you put there.

You should type in “int” as in integer at the beginning of your variable (x = 10) if you really want your “x” to be equal to “10”....

(laughs)

Answer 14

Don’t worry.. I’ve already predicted what would happen if I do that @Deepak Gautam

Answer 15

Hola

Answer 16

Hello