+ 1
Why is the output not 1 2 3 4?
public static void main(String[] args) { int x = 1; while(x > 0) { System.out.println(x); if(x == 3) { break; } x++; } System.out.println(x++); } The output comes out to be 1 2 3 3 If i write (x=x+1) in the last statement, it comes out to be 1 2 3 4. But if (x++) and (x=x+1) are same, why are the outputs not same?
5 Antworten
+ 8
@ADP , see this ... 👍
//btw the difference caused in above question by ++x& x++ is only in printing
https://www.sololearn.com/Discuss/1140298/?ref=app
+ 6
x++ uses the value of x and then increments which basicly means that the old value of x will be used first and then the new value will be used next
++x increments the value of x and then uses it.
++x looks like x+=1.
+ 3
public static void main(String[] args) {
int x = 1;
while(x > 0) {
System.out.println(x);
if(x == 3) {
break;
}
x++;
}
System.out.println(++x);
}
"x++" and "++x" are not the same.
For the answer "1 2 3 4" you need to use "++x".
+ 1
Could u explain further please? (x++) is (x=x+1) right?
and (++x) is?
+ 1
Could u check this code....if i have understood clearly....
https://code.sololearn.com/c2nG7xO2to5x/?ref=app