What is the working of Overloading binary operators.

Question

1.class complex{
2. float x;
3. float y;
4. public:
5. complex(){}
6. complex(float a, float b){
7. x = a; y = b;
8. }
9. complex operator+(complex);
10.
11. };
12.complex complex::operator+(complex c){
13. complex temp;
14. temp.x=x+c.x;
15. temp.y=y+c.y;
16. return (temp);
17.}
18.int main(){
19. complex c1,c2,c3;
20. c1=complex(2.2, 4.4);
21. c2=complex(3.3, 5.5);
22. c3=c1+c2;
23.}

what happen at line 14 & 15 means what is the value of x&y that time

Answer 1

Ignoring compile errors due to typos, c3.x is 5.5 and c3.y is 9.9 after line 22 because line 14 adds 2.2 & 3.3 together from c1 & c2 and line 15 adds their 4.4 & 5.5 together.

c1+c2 can be thought of as c1.operator+(c2). Therefore, the x & y in those lines are c1.x & c1.y, while c is c2.

Answer 2

c1.operator+(c2) makes c1 as this in the function. x & y are this.x and this.y. The this is optional.

Answer 3

ok thanks.

Answer 4

John Wells you mean by default x & y is treated as c1.x & c1.y?