output of python programming

Question

import random

class VagueList:
def __init__(self, cont):
self.cont = cont

def __getitem__(self, index):
return self.cont[index + random.randint(-1, 1)]

def __len__(self):
return random.randint(0, len(self.cont)*2)

vague_list = VagueList(["A", "B", "C", "D", "E"])
print(len(vague_list))
print(len(vague_list))
print(vague_list[2])
print(vague_list[2])

output

6
7
D
C
>>>

overriding of len()....??
indexing() use...??

Answer 1

Nope! No overriding

It's working according to your code:
output of 6 and 7 are valid since your __len__ method returns a random value between 0 and 10
len(["A", "B", "C", "D", "E"]) * 2 == 5*2 == 10

So, you are actually doing a return of random.randint(0, 10). This will give different output for each call of ur len merhod.

Same thing applies to outputs of vague_list[2]

Answer 2

Ok.
When you created the object/instance vague_list, of class VagueList, u pass the list ["A","B","C","D","E"] to the argument cont. (the constructor handled this)

the possible values of random.randint(-1, 1) are -1, 0, 1.
vague_list[2] implies index = 2.

Say random.randint(-1, 1) gives you 1;
So return self.cont[index + random.randint(-1, 1)]==>return self.cont[2+1] ==>return ["A","B","C","D","E"][3] which gave the output D.

If random.randint(-1, 1) gives you 0;
it implies return self.cont[index + random.randint(-1, 1)] ==> return self.cont[2+0] ==> return ["A","B","C","D","E"][2] which gave output C.

If random.randint(-1, 1) gave -1;
U would get output B.

Answer 3

how the functions are being called here....??

return self.cont[index + random.randint(-1, 1)] #WORKING OF THIS STATEMENT...??

Same thing applies to outputs of vague_list[2] #HOW...???