How to send data from a recyclerview to another recyclerview ????

Question

Hi guys i need some help in java im trying to make a recyclerview that have some items and i wanted whenever someone clicked on one item it took him to the other recyclerview but with the data i set it for ?? PLS HELP

Answer 1

Hmm, I would have thought that you would want to launch another activity when a recyclerview item is clicked. This new activity would also contain a recycler view. Is my assumption correct or is it something else?

Answer 2

Sorry Icemail I don't really know C++, but the underlying algorithm is pretty simple though. I used a math approach in the code.
(X + Y) ^ n = nCr(X^(n-r) * Y^r) + ...
where r is from 0 to n and nCr means n combination r

Answer 3

Icemail on second thought, check here. Users submitted answers in all kinds of languages
https://www.sololearn.com/Discuss/975880/?ref=app

Answer 4

Icemail if you need assistance with anything unrelated to this post please use the Q & A to ask your own unique question. This will increase your chances of getting help 😃

Answer 5

#Yerucham yes bro but the second recyclerview i want it to display content of the item clicked in the first recyclerview. do i have to make for every item a recyclerview or just one will do the thing ?? thanks in advance bro

Answer 6

Yerucham, I was checking through your codes and stumble upon a code to obtain the terms of binomial expansion......can you please do that once again using c++? I'll be forever thankful if you do so!!

Answer 7

I need help with the code below. I keep on seeing error message like "invalid data types....float[int]"

//LU Decomposition for
#include<iostream>
using namespace std;
int main() {
int n,i,k,j,p,sum;
float a[10][10],l[10][10]={0},u[10],b[10],z[10],x[10];

cout<<"Enter the order of matrix";
cin>>n;
cout<<"Enter all coefficients of equ";
for(i=1;i<=n;i++)
{
cout<<"\nRow "<<i<<" ";
for(j=1;j<=n;j++) {
cin>>a[i][j]; }
}
cout<<"Enter elements of b matrix";
for(i=1;i<=n;i++){
cin>>b[i]; } //LU decomposition
for(k=1;k<=n;k++)
{
u[k][k]=1;
for(i=k;i<=n;i++)
{
sum=0;
for(p=1;p<=(k-1);p++){
sum+=l[i][p]*u[p][k];}
l[i][k]=a[i][k]-sum;
}

for(j=(k+1);j<=n;j++)
{
sum=0;
for(p=1;p<=(k-1);p++){
sum+=l[k][p]*u[p][j]