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Why it alert's string when you enter a number.?
8 Antworten
+ 2
It's the default return type from a prompt.
I'd suggest to use the isNaN statement to test (is Not a Number), which understands if the value of the variable is not usable as a number. Just add the not logical operator (!) and you've done.
function a() {
var b = prompt("Enter s.th");
var type;
if (!isNaN(b))
type = 'It is a Number!';
else
type = 'It is a String!';
alert(type);
}
a()
+ 2
because the default value of a type of data received in a prompt is string
+ 1
Obviously we can reverse the code to be more straightforward:
if (isNaN(b))
type = 'It is a String!';
else
type = 'It is a Number!';
+ 1
Yes I underestood thanks
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Ok thanks
0
I have a question you wrote
if(!isNaN(b)){
type="it's a number"
}
it means if b is not a number
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Please note the ! before the isNaN statement, that means it will reverse the value of isNaN(b).
// User wrote 7
isNaN(b) = false
!isNaN(b) = true
//User wrote “hello”
isNaN(b) = true
!isNaN(b) = false
0
Ok