Write a program that prints the first 100 members of the sequence 2, - 3, 4, -5, 6, -7, 8.

Question

Can we work on this? What could be the possible approach?
The problem is, the c# program should print the first 100 members of the sequence.
Implying that it is an infinite sequence to be continuous with the '...' sign after the 100th element.

Good luck!

Answer 1

Which language, Javascript?

var i;
for (i = 2; i <= 100; i++) {
if (i % 2 == 0)
document.write(i+"<br>");
else
document.write (i*-1+"<br>");
}

Answer 2

#Python oneliner
print(*[i*(1,-1)[i%2] for i in range(2,103)])

Answer 3

Hi ThiemTD In your code i = b, but "b" what does it do? Missing data entry? Or "b" is equivalent to any value you want? =)

Answer 4

@Luciano Ariel Caputi,

Yes, It is my mistake. Thanks for your opinion.

Answer 5

Please see more in: https://code.sololearn.com/cqHjVUyD58Zd/#cpp
Thanks

Answer 6

Hi,

I would solve this by incrementing x=x+2 and using an additional variable (y) and either ad the character “-“ as prefix or, better, make y negative by formula *(-1)

My code suggestion for Java: (apologies for bad formatting :)

public class Program
{
public static void main(String[] args)
{
int x=2;
int y;
while (x<=100){
y=(x+1)*(-1);
System.out.println(x);
System.out.println(y);
x=x+2;
}
}
}

Answer 7

This is my solution in C#.

static void Main(string[] args)
{
// This is about the best take.

for (int i = 2; i < 102; i++)
{
if(i % 2 == 0)

Console.Write("{0}, {1}, ", i, (i + 1)*(-1));

}
}