+ 6
Looping through an array
Can someone please explain to me why the answer to this is 0 and not 3.? When looping through the array, doesn’t it stop at 3? Wouldn’t 3 therefore be what I multiplied? var arr = [1,2,3,4]; var x = 1; for (var i = 0; I < arr.length; i++); { x*=i; } alert (x);
6 Antworten
+ 10
It doesn't stop after the first iteration. Observe the code carefully. The loop content is
x *= i
and the value of x is printed after the loop ends.
1 multipled by 0 is 0. 0 is assigned to x.
0 multipled by 1 is 0. 0 is assigned to x.
0 multipled by 2 is 0. 0 is assigned to x.
0 multipled by 3 is 0. 0 is assigned to x.
x is printed.
0 is printed.
+ 10
On the first iteration, the value of i is 0.
Anything multiplied by 0, is 0.
+ 3
It doesn't stop.
after the first iteration x=0
then i =1,2,3,4 and
x = x*i =0
That's why its 0
+ 3
By the way, the alert function is outside of the for loop.
+ 2
So it stops after the first iteration not the last? I thought it would loop through them all. So the answer would be 0123. Thanks Hardy
+ 1
Got it!! Thanks Hatsy. Perfect explanation. Thank you all.