Why isn't the printf and return statement outputting the same value for results?

Question

using c/c++, on codeblocks 17.12
https://code.sololearn.com/cMTJ1J31ycqD/?ref=app

Answer 1

Oh I see. In your code it gives good results, but you have to get paranthesis good. Use:
(-b + sqrt(...)) / (...).
If you wont put () around first expression the divide will evaluate first and then add -b to it.

Answer 2

Return isn't used for printing out the result on console. It just returns value, so you can assign it to variable or pass as an argument.

Answer 3

that's right, but i could output it directly..

int age(int age)
{
return age;
}

int main()
{
cout<<"i am " <<age(1000) <<" years old"<<endl;

return 0;
}

Answer 4

you can do
int val = age(1000);
cout<<"age: "<<val;

return only assign a value to variable or printing this value that return

Answer 5

its a solution to someone, and i want it to be much more readable..

Answer 6

its a solution to someone, and i want it to be much more readable..

Answer 7

found the error
instead of %.2f i wrote %2.f