Does structure copy can handle char array too in c?

Question

code snip>>

#include <stdio.h>
#include <string.h>
typedef struct ST {
char a[50];
}s;

int main() {
s s1,s2;
strcpy (s1.a,"Saga");
s2 = s1;
printf("%s",s2.a);

return 0;
}
output: Saga
How structure copy works internally? Is it behave same in cpp? someone please explain it.

Answer 1

memcpy() is part of a C library, so no. what C uses when you do so is equivalent to a malloc

Answer 2

It is equivalent to a memcpy.
When you do the "=", your computer will blindly copy all bits from one memory location to the other one.

Answer 3

it works the same as with every other variable copy. e.g.:

int a, b;
a = 2;
b = a; //now b is also 2

what really happens here is:

1. memory spaces for 'a' and 'b' are created
2. the value 2 is assigned to the memory space assigned to 'a'
3. a copy of 'a' is created and stored somewhere in an available spot in memory
4. the copy made in step 3 is assigned to the spot in memory assigned to 'b'
5. the spot in memory for the copy created is cleared in order to free up memory

so when you say 's2 = s1', a copy of 's1' is created and stored somewhere and then copied onto 's2' and then deleted to free up memory.

Answer 4

it's what Baptiste E. Prunier explained. a memcpy() is just a way to copy all bits from one memory address to another, but your OS does not use memcpy() to do so. the method it uses achieves the same purpose, though.

Answer 5

🐙evil octopus Does it mean os internally follows memcopy for this?

Answer 6

🐙evil octopus Your answer is not clear. Could you please clarify?