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Is there any command in Python for sound creation?? Using python 3 and 2.7
5 Antworten
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Yes, but without modules it would be hard, by opening a sound file in binary read more, but it is too difficult, when I tried:
(len(open("/storage/emulated/0/S/Sound_files/test1.wav", "rb").read()))
Results about 15000 bytes long binary string for only a sound file of 5 seconds, but this can be done by using some modules, https://pypi.org/
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Thank you, but, umm, I am unable to find a sound module at pypi.orh
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I found a way for sound edition:
I tried to edit 5 second long .wav file it started with:
RIFF\x04\xeb\x02\x00WAVEfmt
I tried to edit 10 second long .wav file it started with:
RIFFD\xe5\x04\x00WAVEfmt
I could index the file and make a sound file sound different, but the length of sound wave were defined inside: RIFF\x04\xeb\x02\x00WAVEfmt
RIFFD\xe5\x04\x00WAVEfmt,
rest of the sound file is just \x<Hex><Hex> thousands of times and some random character s,
I could just move and reverse the Binary string characters in a sound file making weird sounds,
I couldn't self create sounds, because I couldn't use b"\", that caused some errors and using b"//" broked the file for being a binary file.
How much do you know about files and binary strings?
Making sound files without modules needs a lot of knowledge about text printed by:
print(open("Test1.wav", "rb").read())
I am right trying to learn to use it, it is interesting and would be used to create images-, video- and soundfiles.
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thus:
for 5 seconds long sound file:
RIFF\x04\xeb\x02\x00WAVEfmt
In numbers:
82, 73, 70, 70\4\235\2\0, 87, 65, 86, 69, 102, 109, 116
for 10 seconds long sound file:
RIFFD\xe5\x04\x00WAVEfmt
In numbers:
82, 73, 70, 70, 68\229\4\0, 87, 65, 86, 69, 102, 109, 116