List.append (x) problem!

Question

hi every one
I want to know why this code don't want executed

list = [5,3,6,9,7]
list_sqr = []
for x in list :
list.sort ()
x = x**2
list_sqr = list.append(x)
print (list_sqr)

it takes lot of time then error or no results
thanx

Answer 1

some changes

list = [5,3,6,9,7]
list_sqr = []
list.sort ()
for x in list:
x = x**2
list_sqr.append(x)
print (list_sqr)

list.sort() should execute once only
you should append TO list_sqr without assignment to the original list

and another word of advice, do not use the word 'list' as a variable name as it is used as a built-in to convert into a list object

Answer 2

@Rishi Anand way is much more 'pythonian' in its loop approach

python provides many 'shortcuts' such as that one for manipulating data (filter, map, reduce, etc....)

Answer 3

The real power of python lies in exploiting its library.

lst = [5,3,6,9,7]
lst.sort()
lst_sqr = [x**2 for x in lst]
print(lst_sqr)

Answer 4

thanks gays I can see clearly now

Answer 5

I'm straight... sorry