Can a function be called from another function that is not main?

Answer 1

Yes, you can even call the function itself. However, this may cause an infinite loop if there is no break condition. This is called recursion.

Answer 2

yes

Answer 3

i'm sure that's not what you want but.
#include <iostream>
using namespace std;

void simple()
{
cout<<"easy"<<endl;
}

int main()
{
simple();
}

Answer 4

yes

Answer 5

yes the fuction can be called from another function but if a function calls itself it's recursion...

Answer 6

yes you can

Answer 7

yes you can

Answer 8

of course :)

Answer 9

Yes

Answer 10

Yes ,
In recursion you can call..

Answer 11

yes , you can call .. to prevent it from infinite loop use break

Answer 12

I think it's c++

Answer 13

yes you can but define the function on up of other function

Answer 14

sure!!
have a nice day and check out my codes ;)

Answer 15

yes sure for example:
int f(int n){
if(n == 1||n==2)
return 1;
return (f(n-1)+f(n-2));
}
int main(){
cout << f(4);
return 0;
}

this is Fibonacci 4

Answer 16

yes it can, it has two ways:
1) the "called function" is defined/written/coded before the "caller function"
example:
float pi()
{
return 3.1412; //or some other code
}
float area( float radius)
{ return radius*radius*pi(); }

2) a prototype is declared in the "caller function", if this approach is taken, the "called function" can be anywhere in the program.
float area (float radius)
{ float pi();
return radius*radius*pi(); }
float pi()
{ return 3.1412; }

note: if function pi had parameters, its prototype would be:
float pi(int);
float pi(float);
would be like telling it: "there is a function called pi somewhere in the program and it takes an int/float/..."

as for the "function calling itself" mentioned by an earlier answer, that has special rules and is called as "recursion".