In the code in class B , it is given - object.do("B") . And the result is also printed as "B" . Then what is the purpose of the

Question

class A {
public void do() {
System.out.println(''A'');
}
public void do(String str) {
System.out.println(str);
}
}
class B {
public static void main(String[ ] args) {
A object = new A();
object.do(''B'');
}
}

Answer 1

It compiles the second do() method as this one requires a String as an arguement.

A object=new A(); creates an instance of class A.

object.do("B"); will print B