Is anything wrong here

Question

#include<stdio.h>
#include<math.h>
void main()
{
int t,h;
float c;
printf("enter c,t,h");
scanf("%d %d %f",&c,&t,&h);
if(((h>50)&&(c>.7)&&(t<5600))||((h<50)&&(c<.7)&&(t<5600))||((h<50)&&(c>.7)&&(t>5600)))
printf("grade6");
else
printf("poor steel");
#include<stdio.h>
#include<math.h>
void main()
{
int t,h;
float c;
printf("enter c,t,h");
scanf("%d %d %f",&c,&t,&h);
if(((h>50)&&(c>.7)&&(t<5600))||((h<50)&&(c<.7)&&(t<5600))||((h<50)&&(c>.7)&&(t>5600)))
printf("grade6");
else
printf("poor steel");

}

}

Answer 1

Hi Iulian Gudumac

Dipu Ojha knows this already as in the previous post

please read posts before commenting

Answer 2

Yes, the code is repeated

and sorry i dont fully understand C

Answer 3

You inserted code twice and made error in scanf. Here is the corrected version.

#include<stdio.h>
#include<math.h>

void main()
{
int t,h;
float c;

printf("enter c,t,h");

/* Error was here
scanf("%d %d %f",&c,&t,&h);
*/
scanf("%f %d %d",&c,&t,&h);

if(((h>50)&&(c>0.7)&&(t<5600))||((h<50)&&(c<0.7)&&(t<5600))||((h<50)&&(c>0.7)&&(t>5600)))
printf("grade6");

else
printf("poor steel");
}

Answer 4

There was also an error in scanf()

The first variable read is of float type so use %f for var c.
The remaining two variables are of int type, so use %d for vars t, h.

Answer 5

I don't C ;)

Answer 6

Pay attention to the variable types inside the scanf. You tried to read a float variable c using %d. Should be used %f for float varible c. For the int variables t,h should be used %d%d.

as result,
%d %d %f
will read
int int float

I hope this helps.

Answer 7

thanks

Answer 8

oo only that nothing in the coding stuff