how would I continue to run the program over again without closing and starting it up again?

Question

#include <stdio.h>

int greatestCommonDivisor(int m, int n)
//This function implements the Euclidian Algorithm
{
int r;

/* Check For Proper Input */
if ((m == 0) && (n == 0))
{
printf("Bye");
return 0;
}
else if ((m <= 0) || (n <= 0))
{
printf("Wrong input. ");
printf("Please enter positive integers. ");
return 0;
}
do
{
r = m % n;
if (r == 0)
break;
m = n;
n = r;
} while (0);

return n;
}

int main(void)
{
int num1, num2;
printf("Please enter two numbers: ");
scanf("%d %d", &num1, &num2);
int gcd = greatestCommonDivisor(num1, num2);

if (gcd >= 1)
{
printf("The GCD of %d and %d is %d\n", num1, num2, gcd);
}
getchar();
return 0;
}

Answer 1

#include <stdio.h>

int greatestCommonDivisor(int m, int n)
//This function implements the Euclidian Algorithm
{
int r;

/* Check For Proper Input */
if ((m == 0) && (n == 0))
{
printf("Bye");
return 0;
}
else if ((m <= 0) || (n <= 0))
{
printf("Wrong input. ");
printf("Please enter positive integers. ");
return 0;
}
do
{
r = m % n;
if (r == 0)
break;
m = n;
n = r;
} while (0);

return n;
}

int main(void)
{
char repeat;
do {
int num1, num2;
printf("Please enter two numbers: ");
scanf("%d %d", &num1, &num2);
int gcd = greatestCommonDivisor(num1, num2);

if (gcd >= 1)
{
printf("The GCD of %d and %d is %d\n", num1, num2, gcd);
}
getchar();
printf("Exit?: y/n");
scanf("%c", &repeat);
}while(repeat != 'y');
return 0;

}

Answer 2

well without having to say repeat.. it keeps going until the user enter 0 0..

Answer 3

How about this?:

do {
int num1, num2;
printf("Please enter two numbers (other than 0): ");
scanf("%d %d", &num1, &num2);
if(num1 == 0 || num2 == 0)
return 0;
int gcd = greatestCommonDivisor(num1, num2);

if (gcd >= 1)
{
printf("The GCD of %d and %d is %d\n", num1, num2, gcd);
}
getchar();

}while(true);
return 0;