Help me with this if you don't mind

Question

#include <iostream>
#include <vector>
#include <numeric>

using namespace std;

class process{
public:
void start(){
string a;
string result;
cin >> a;
int b = 0;
int siz = 0;
int word = 0;
string n;

shift.push_back(a);

for(int i = 0; i<shift[word].size(); i++){
letters.push_back(a.at(b));
copy.push_back(a.at(b));
b++;

}

do{
letters.insert(letters.end(), copy[siz]);
for(int i = 1; i<letters.size(); i++){
n =+ letters[i];
}
cout << n <<"\n";
siz++;
}
while(siz<b);
}

private:
vector<string> shift;
vector<char> letters;
vector<char> copy;
};

int main(){
process ok;
ok.start();
}

Answer 1

What is this code supposed to do? what is the expected final result? try first to change "n =+ letters[i];" into "n += letters[i];" : )

Answer 2

lpang, thanks a lot, i missed that😁 (here is quest by the way: https://www.sololearn.com/learn/9885/?ref=app)

Answer 3

yoohoo gonna post my final work;
#include <iostream>
#include <vector>
#include <numeric>

using namespace std;

class process{
public:
void start(){
string a;
string result;
string n;

int c = 1;
int b = 0;
int siz = 0;
int word = 0;

cin >> a;

shift.push_back(a);

for(int i = 0; i<shift[word].size(); i++){
letters.push_back(a.at(b));
copy.push_back(a.at(b));
b++;
}

do{
letters.insert(letters.end(), copy[siz]);
for(int i = c; i<letters.size(); i++){
n += letters[i];
}
c++;

cout << n <<", ";
siz++;

n.clear();
}
while(siz<copy.size());
}

private:
vector<string> shift;
vector<char> letters;
vector<char> copy;
};

int main(){
process ok;
ok.start();
}

Answer 4

it's so complicated, any efforts appreciated🤗

Answer 5

Good job! congratulations and good luck! : )