Intervals in Python3

Question

Hi! Could someone teach me how to create an interval in Python? I've already searched on the internet but came without a good answer.
I get an error whenever I type ---> x=interval ( [2,y-1] ). I need integers to build my very first program.
I tried to import interval from interval module but Py doesn't recognize it.
Thanks in advance!

Answer 1

Virgil Baclanov Let's say you want to divide the integer 294 by every integer in the interval from 13 up to 54.

The results can make a list like this:

x = 294
results = [x/y for y in range(13, 55)]

Observation: the `%` symbol is for modulus operation, not for division.

Answer 2

Assume you need an interval from 1 to 9.
So you do:

my_interval = list(range(1, 10))

# the end of the interval is non-inclusive
# so if you need an interval from "m" up to "n", you should do range(m, n+1)

Answer 3

You would do something like this:

new_list = []

for i in interval:
new_list.append(i % 5)

print(new_list)

--------------

To shorten that you could do:

print([i % 5 for i in interval])

Answer 4

You might be looking for range objects:

>>> x = range(50, 100)

>>> len(x)
50

>>> 83 in x
True

>>> x[3]
53

>>> x[-1]
99

>>> x[13:24]
range(63, 74)

>>> for i in range(11): print(i*i, end = ' ')
0 1 4 9 16 25 36 49 64 81 100

Answer 5

Eduardo Petry Just A Rather Ridiculously Long Username
Thanks a lot, guys! Both versions seem to work for my program. Have a nice day!

Answer 6

Oh okay thanks, happy coding!

Answer 7

Just A Rather Ridiculously Long Username happy coding, too!

Answer 8

Eduardo Petry thanks! But, what do I do when I wanna divide an integer by *each* integers in the interval?
example -- I type ---> if dividend%interval==0: ...
but Phyton is telling me that it is an unsupported operand type(s) for %: 'int' and 'list'