Hey friends! Please explain me this code and say why its output is reversed?

Question

#include <iostream>
using namespace std;

int main() {
int N =345,sum =0;
while(N>0){
sum=N%10 +sum*10;
N /=10;
}
cout<<sum;
return 0;
}
//output is 543

Answer 1

N = 345, sum = 0

while(N > 0)
{
//First iteration (345 > 0)
//345 % 10 = 5
// 0 * 10 = 0
sum = 5 + 0 = 5
N /= 10 --> N = 34

//Second iteration (34 > 0)
//34 % 10 = 4
//5 * 10 = 50
sum = 50 + 4 = 54
N /= 10 --> N = 3

//Third iteration (3 > 0)
//3 % 10 = 3
//54 * 10 = 540
sum = 540 + 3 = 543
N /= 10 --> N = 0 (int)

//Fourth iteration (0 > 0) false
//Exits from the loop
}

sum = 543
//Number is reversed

Answer 2

mod 10 will kind of detach the last number every time.. so you can see first 5 comes out .. similarly 4 and then 3... this is how it is reversed.. take your pen and paper.. start calculating

Answer 3

%mod sign is used for taking the reminder if u wanna take last digit to first take the remainder by moduling 10 and after that here number is divided by 10 so that there is no uae of last number as qe preserve in sum

Answer 4

где русские то , ебаный в рот