Explain this plis

Question

for i in range (10):

if not i%2==0:
print (i+1)

Answer 1

for i in range(10):

if not i%2==0:
print(i+1)

result is

i=0 #0 divided by 2 leaves a remainder 0 so nothing happens but it goes to the next number

i=1 #1 divided by 2 leaves a remainder 1 which is not equal to 0 so the program prints i+1 that is 1+1=2

i=3 #3 divided by 2 leaves a remainder which is not equal to 0 so the program prints i+1 that is 3+1=4

i=4 #4 divided by 2 leaves a remainder 0 so nothing happens but it goes to the next number

i=5 #5 divided by 2 leaves a remainder 3 which is not equal to 0 so the program prints i+1 that is 5+1=6

i=6 #6 divided by 2 leaves a remainder 0 so nothing happens but it goes to the next number

i=7 #7 divided by 2 leaves a remainder 1 which is not equal to 0 so the program prints i+1 that is 7+1=8

i=8 #8 divided by 2 leaves a remainder 0 so nothing happens but it goes to the next number.

i=9 #9 divided by 2 leaves a remainder 1 which is not equal to 0 so the program prints i+1 that is 9+1=10

end

the real result is

2
4
6
8
10

#so it prints all the even numbers in the range 0 to 10