hello can someone please explain this code for me ! thank you 🤗

Question

def f(r) :
j =range(r)
e=eval("*".join([str(i+2)for i in j]))
return e
print(f(3))

Answer 1

The last line has an error, too many parentheses ;)

Basically what the code does is it takes an input of 3 and:
- builds a range of 0, 1, 2
- iterates through it and builds on-the-fly a list of 0+2, 1+2, 2+2 (so 2, 3, 4)
- the str() method converts those numbers into strings and join() makes them glued together with an asterisk sign between the numbers (2*3*4)
- finally eval() evaluates the expression (2*3*4=24)
- the result is printed to the screen

Answer 2

thank you so much 😃Kuba Siekierzyński

Answer 3

no one The problem is with the line 2, not 3. You have to close the parenthesis. Or as a matter of fact, dispose of str() altogether. Input() already returns a string ;)

Answer 4

Got it 😃 thank youuu 💛

Answer 5

hh I do need some coffee 😅 thank youuu sir 💛❤

Answer 6

mrr Kuba Siekierzyński can you please figure out with me whats wrong with line 3 !! its not an invalid syntax tho

msg=str(input("saisir votre message:"))
cle=str((input("saisir votre cle:"))
LETTERS = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
res=''
i=0
for char in msg:
begin=LETTERS.find(cle[i])
pos=LETTERS.find(char)
indice=pos+begin
if indice>25:
indice-=26
res+=LETTERS[indice]
i+=1
if i>=len(cle):
i=0
print(res)

Answer 7

The loop starts with i == 1.
At first go it prints i+1, so 2.
Then i itself is multiplied by 2 and is now 2.
The loop goes off again and prints i+1. Since i is now equal to 2, i+1 is 3 and this one is printed. Meanwhile i is again multiplied by 2 and is now equal to 4. The loop's next cycle prints 4+1, so 5 and multiplies i by 2 again (i is now equal to 8. The last cycle prints out 8+1, so 9 and multiplies i by 2 again.
Since i is now 16, so greater than 10, the loop ends.

in fact, it's easier to think of this as a cycle similar to 1, 2, 4, 8, etc. BUT +1 :)

Answer 8

mr Kuba Siekierzyński would u please explain this one too ! didn't understand the principe !
i=1
while i<=10:
print(i+1)
i*=2
>>>2359
and really thanks a lot in advance 💛💚

Answer 9

hallow guy

Answer 10

yes get me

Answer 11

molly
mr Kuba Siekierzyński would u please explain this one too ! didn't understand the principe !
i=1
while i<=10:
print(i+1)
i*=2
>>>2359

In first execution of while loop. It's true with i=0, then print i+1, i.e. equal to 2. Here print function just print without moving cursor to next line. Before completing first loop 'i' has been modified by i*=2 (i=i*2). so finally after completing first loop output (print) is 2 and i is 2.

It'll iterate similarly in the next loops until the value of i will satisfy the while loop condition i<=10

In 2nd loop
i=2, while condition=true, output=3 (on the same line), modified i=4

In 3nd loop
i=4, while condition=true, output=5 (on the same line), modified i=8

In 4nd loop
i=8, while condition=true, output=9 (on the same line), modified i=16

In 5nd loop
i=16, while condition=false, loop will break and execute the next consecutive statements. output=nothing