In what order does functions work?

Question

function factorial(n) {
if (n === 0) {
log('Base case reached');
return 1;
}
log('n - 1 is ' + (n - 1));
return n * factorial(n - 1);
}
log(factorial(4));

In this small chunk of code, we calculate the factorial of a number. But I have a question: The part where the code goes: return n * factorial(n-1); , does it first count the parenthesis then do the function, or does it input straight "n-1" to the function?

Answer 1

It counts it first so that it will be assigned to the arguments.