Please explain the logic

Question

import functools
list=[1,2,3,4,5]
R_list=[functools.reduce(lambda x,y: x*y,list)]
print(R_list)

Answer 1

functools.reduce(function, iterable[, initializer])

Apply function of two arguments cumulatively to the items of sequence, from left to right, so as to reduce the sequence to a single value. For example, reduce(lambda x, y: x+y, [1, 2, 3, 4, 5]) calculates ((((1+2)+3)+4)+5).

Source: https://docs.python.org/3/library/functools.html

Answer 2

functools.reduce execute a function with items of an iterable by passing couple of parameter starting from left to right of iterable then passing the result of function and next item for next function call while all items are processed, then return the result. In yourexample, this happen:

1) first two items are multiplied 1*2=2
2) the result is multiplied for 3rd items 2*3= 6
3) the result is multiplied for 4th items 6*4= 24
4) the result is multiplied for 5th items 24*5= 120
5) functools.reduce return 120

For more details see here
https://docs.python.org/3/library/functools.html

Answer 3

thank you KrOW Anna

Answer 4

Anna Kuba Siekierzyński