How to write a C Function to swap elements of 2 arrays according to the smallest array in size

Question

I need it to be in one function, just call it in main like this code, but this doesn't work:

#include <stdio.h>
#include <stdlib.h>

void swap(int *arr1, int arr1_size, int *arr2, int arr2_size)
{
int temp;
temp = *arr1;
*arr1 = *arr2;
*arr2 = temp;

int i;
int size = (arr1_size < arr2_size? arr1_size : arr2_size);

for(i=0;i<size;i++)
{
printf("arr1=%d \n arr2=%d \n",arr1[i],arr2[i]);
}

}
int main()
{
int a[5]={1,2,3,4,5};
int b[3]={10,20,30};
swap(&a[5], 5, &b[3], 3);
return 0;
}

-------------------------------------------------------------
I tried this outside main and its okay, but this is not what I want:

#include <stdio.h>
#include <stdlib.h>

void swap(int *arr1, int *arr2)
{
int temp;
temp = *arr1;
*arr1 = *arr2;
*arr2 = temp;
}

int main()
{
int i;
int a[5]={1,2,3,4,5}; int a_size=5;
int b[3]={10,20,30}; int b_size=3;
int size = (a_size < b_size? a_size : b_size);
for(i=0;i<size;i++)
{
swap(&a[i], &b[i]);
printf("a=%d \n b=%d \n",a[i],b[i]);
}

return 0;
}

the answer is:
a=10
b=1
a=20
b=2
a=30
b=3
and the other 2 elements have been removed, is it correct?

Answer 1

#include <stdio.h>
#include <stdlib.h>

void swap(int*a,int*b,int a_size,int b_size){
int size = (a_size < b_size? a_size : b_size);
int i;
for(i=0;i<size;i++)
{
int temp = a[i];
a[i] = b[i];
b[i] = temp;

printf("a=%d \n b=%d \n",a[i],b[i]);
}
}

int main()
{
int i;
int a[5]={1,2,3,4,5}; int a_size=5;
int b[3]={10,20,30}; int b_size=3;
swap(a,b,a_size,b_size);

return 0;
}