Please help me with the logic

Question

list1 = []
list2 = []
for i in range(5)[::-1]:
list1.append(i)
for j in list1[::-2]:
list2.append(j+1)
print(list1[2])

Answer 1

Hi AMAN TOMAR
Posting numerous times in a row is borderline spam.

A better way to ask specific people for help (as you seem to have done) would be to create a new code that contains the problem and tag the people in the comments section.

Answer 2

jay was not aware about it .just wanted some help.thnks

Answer 3

KrOW thank you 😊

Answer 4

JOY KrOW JeMa ^_^ 🇨🇩 Anna

Answer 5

AMAN TOMAR in first loop range(5) return an range object. You can view this like a tuple (0,1,2,3,4). At this "tuple", you apply the slice operator [::-1] that in practice reverse the tuple then its (4,3,2,1,0). After this, list1 will be a list like [4,3,2,1,0].

In second loop, j will iterate on a new array created by slice operator of list1 that reverse it [0,1,2,3,4] and get like items every 2 items of this reversed array starting from first then j will iterate on [0,2,4].
You build list2 by adding one at every j then list2 will be [1,3,5] and at end third list2 item is printed (5)

P.S. Like jay said, if you tag specific users use code comments