Can a random.choice be made into a variable?

Question

Can you do something like

a = random.choice()

and when you need to fill the parameters you can do something llike
if b == 5
a = random.choice(c)

Answer 1

random.choice is a function that returns what it chooses from the iterable.

So yes, you can store that choice and use it later.

Answer 2

In case you don't want to use such a long word, this is also valid:

import random

a = random.choice
print(a([1, 7, 3]))

Instead of calling the function, we're just giving it another name. But if that is your goal, I'd recommend

from random import choice as a

print(a([1, 7, 3]))

Answer 3

Yes you can, why dont you try try it in code playground ? its faster than waiting for someone to answer

Answer 4

Fbia34
the method 'choice' from random, expects a sequence argument,
so if you do this:

a = random.choice()

you will get an error telling you that.

Answer 5

Fbia34 The problem with your only code is not that you used random.choice wrongly, but you are missing one comma. here i corrected for you:

https://code.sololearn.com/cbU63AFo2OeZ/?ref=app

Answer 6

Fbia34 Welcome😉
try code more
basketballgirl's 800 upvote game is by random.choice
you can do it too~

Answer 7

╰☆☆ S͎p͎e͎a͎r͎y͎ ☆☆╮ that's actually what this question is for, it's just a variation instead of earth it's space

Answer 8

╰☆☆ S͎p͎e͎a͎r͎y͎ ☆☆╮ oh this isn't for the art gen (which I made for a friend who said it worked fine) but thanks lol I didn't catch that

Answer 9

Fbia34 heres mine from the halloween contest:

https://code.sololearn.com/c22kNFrS19ds/?ref=app
edit:
this is made for ur question.

Purrfect debug,
withit