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What am I missing here??
Read the following and pls explain me what im doing wrong : int a = 3; int b = 2; b = a++; cout << ++b; What will be printed out "b" ? My answer is 5. where, b = a++ means, b = 3 + 1; so b = 4 so, cout << ++b; means 1 + 4 = 5 zo it will cout out 5......right???
3 Antworten
+ 2
nope.
a++ is not a+1. Its AFTER the operation , a+1
and ++b is BEFORE the operation
+ 1
no, a in line 3 will be incremented after the line 3, so b gets old value of a which is 3. in line 4 b becomes 4 because incrementation is done prior the execution of line..
a=++x is like
x=x+1
a=x
a=x++ is like
a=x
x=x+1
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b = a++ is a post increment operator.
1. b = a // b = 3
2. a = a + 1 // a = 4
to get the answer of 5, do
b = ++a, which is the pre increment operator.
1. a = a + 1 // a = 4
2. b = a // b = 4