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Please give me a proper solution of this program and also give the explanation how output will comes ?
#include<stdio.h> #include<string.h> #include<conio.h> int main() { char* c="GAMESOFTHRONE18"; char* p=c; printf("%d",(int) strlen (c+2[p]-6[p]-1)); return 0; } //Output is:9
2 Antworten
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"Then c is offset by 6 so strlen is passed "FTHRONE18" which contains 9 characters."
I didn't realize that until
printf("%s", (c + 2[p] - 6[p] - 1));
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c and p contains the address to the beginning of the string "GAMESOFTHRONE18".
2[p] is identical to *(p+2), which in turn is the same as p[2], or the character at index 2, which is M.
With the same logic 6[p] would then match the character F.
The ascii value for M is 77 and 70 for F.
77 - 70 = 7 - 1 = 6.
Then c is offset by 6 so strlen is passed "FTHRONE18" which contains 9 characters.