what is wrong here??

Question

#include <stdio.h>

void Print(int *(num)[3])
{
//printing 5//
printf("%d",*(*(num+1))) ;
}
int main()
{
int num[2][3]= {{2,3,4},{5,6,7}} ;
Print(num) ;
}

I am practicing on passing multi dimensional arrays to functions. In the program above, I am passing a 2D array to a function Print( ) which simply prints an element in the array. I dont understand what is wrong here . My parameters do seem right cuz the function
Print ( ) receives an array of pointers of size 3 which is what i have declared as my parameter. However, my compiler shows an error saying that its an incompatible pointer type. Could anyone explain why that is the case?

Thanks!!

Answer 1

Thanks alot Bennett Post. That must have taken alot of effort to write. I truely appreciate the effort.
You really did clarify alot of things for me.
Once again, thanks alot!!😊

Answer 2

Bennett Post, i do understand that num[2][3] is considered valid and the program does work but i dont understand why *(num)[3] is considered invalid since both of them do mean the same thing dont they??