filling the blanks to define a function that takes two numbers as arguments and returns the smaller one min (x,y) if x<=y return

Question

????

Answer 1

def : return

Answer 2

def shorter(x,y)
if len (x) <len (y):
return x
else:
return y

Answer 3

The solution is:

def
min(x, y):

if x<=y
:

return x

else:

return
y

Answer 4

def smaller(x,y):
if x<=y:
return x
else:
return y

Answer 5

def
:
return

Answer 6

answer:

def
min(x, y):

if x<=y
:

return x

else:

return
y

Answer 7

def shortest_string(x , y):
if len ( x ) <=len(y):
return x
else:
return y

Answer 8

def min(x,y):
if x<=y:
return x
else:
return y

Answer 9

idk the answer! can you please tell me it?

Answer 10

def smaller (x,y):
if x<=y
return x
else:
return y

Answer 11

def min(x,y):
if x<=y:
return x
else:
return y

Answer 12

hbuioehuivrehvyuevbuivcfencuiecnbduixneuirvfnbvubofuincuidc tell me the answer