Why does the following code only produce an integer?

Question

Please review the below. I totally get that if x was declared as an INT then the answer should be 3 (and we could use % to get the remainder). What I don't understand is why the code below still returns an answer of 3. I declared x as a float, so shouldn't the answer be 3.33?

#include <iostream>
using namespace std;

int main()
{
float x = 10 / 3;
cout << x;
return 0;

// Returns 3, why not 3.33? //
}

Answer 1

Jamie💐 Thanks! So you are saying that by rule the division operator always returns an INT value even if the variable is declared as a float?

Answer 2

Jamie💐 Awesome...will give it a whirl...thanks!