Why wont it miltiply correctly

Question

#include <iostream>
using namespace std;

int main()
{
int a, b;
cout << "Enter a number \n";
cin >> a;

cout << "Enter another number \n";
cin >> b;
int sum=a+b;
if (a, b =a+b)
cout << sum;

int product=a*b;
if (a, b=a*b)
cout<<product;

return 0;
}

Answer 1

"but I was using them because I wanted to let the user choose to add or multiply the two numbers"

It demands to implement your solution differently. For example

#include <iostream>
using namespace std;

int main()
{
int a, b;
cout << "Enter a number \n";
cin >> a;

cout << "Enter another number \n";
cin >> b;

int choice;
cout << "1) Add\n"
<< "2) Multiply\n";
cin >> choice;

switch (choice) {
case 1:
cout << "Sum: " << a+b << endl;
break;
case 2:
cout << "Product: " << a*b << endl;
break;
default:
cout << "Wrong choice!\n";
}

return 0;
}

Output:

Enter a number
5
Enter another number
4
1) Add
2) Multiply
2
Product: 20

Answer 2

Because what you've done inside `if` statements have nothing to do with summation and multiplication and mess everything after the first `if` statement.

#include <iostream>
using namespace std;

int main()
{
int a, b;
cout << "Enter a number \n";
cin >> a;

cout << "Enter another number \n";
cin >> b;

int sum=a+b;
cout << "Sum: " << sum << endl;

int product=a*b;
cout << "Product: " << product;

return 0;
}

Output:

Enter a number
5
Enter another number
4
Sum: 9
Product: 20

_____
For more info about the comma operator visit: https://en.cppreference.com/w/c/language/operator_other#Comma_operator

Answer 3

I see what you're saying but I was using them because I wanted to let the user choose to add or multiply the two numbers