I could not understand what i have done ..i need some guidence...

Question

#include <iostream>
using namespace std;

int main()
{
int count = 0;
int x[2][3]={{2,3,4},{8,9,6}};
for(int i=0,j=2;i+j>=-30;i++,j=j-3){
cout<<x[i][j]<<endl;
count++;
}
cout<<"\n\nNumber of 4:"<<count;
return 0;
}

before using loop i did this

cout << x[0][2] << endl;
cout << x[1][-1] << endl;
cout << x[2][-4] << endl;
cout << x[3][-7] << endl;
cout << x[4][-10] << endl;
cout << x[5][-13] << endl;

Answer 1

Whenever you want to understand, you print what you don't understand out.

In your case, you need to do this:
cout<<"i: "<<i<<", j: "<<j<<endl;

https://code.sololearn.com/c29rkGtIeMU8/?ref=app

Is the mist cleared now?

Answer 2

More clearly like this...........but i am still confused.....

#include <iostream>
using namespace std;

int main()
{
int count = 0;
int x[2][3]={{2,3,4},{8,9,6}};
for(int i=0,j=2;i+j>=-30;i++,j=j-3){
cout << "x[" << i << "][" << j << "]: ";
cout << x[i][j]<< endl;
count++;
}

cout<<"\n\nNumber of 4:"<<count;
return 0;
}

Answer 3

Good that you altered the cout to makes thing even clearer.
Can you tell me, for the six numbers stored in x, how do you address these six numbers?

Answer 4

Sir what i actually need to get guidance is about how the result i.e 4 is coming....

Answer 5

Yes and I am trying to tell you why the result is always 4
Now, in your x, it is two by three, can you try to test in your code :
x[0]
x[1]
x[0][0]
x[0][1]
and so on
What do you find out?