Why the output is "Your grade is = 67" when i declare grade as 'int'?

Question

public class Test {

public static void main(String args[]) {

int grade = 'C';

switch(grade) {
case 'A' :
System.out.println("Excellent!");
break;
case 'B' :
case 'C' :
System.out.println("Well done");
break;
case 'D' :
System.out.println("You passed");
case 'F' :
System.out.println("Better try again");
break;
default :
System.out.println("Invalid grade");
}
System.out.println("Your grade is = " + grade);
}
}
If grade is 'char' the output is 'your grade is C'.

Answer 1

int grade = 'C' // it initializes the variable grade to the ascii value of the character 'C', which is 67

Each character has a corresponding ascii value. Check the link below.

https://www.cs.cmu.edu/~pattis/15-1XX/common/handouts/ascii.html

Answer 2

First of all the compiler throws an type error in the intialization of grade.
and as you said it will print ' your grade is c' if you have declared appropriate data type for grade.
else there will be no compilation of the code(to bytecode).