Why do this code always returns that the value of nx is 0.0?

Question

n1=float(input("n1"))
n2=float(input("n2"))
r=n2-n1
nx=str(input("Nx: "))
nx=float()
def aritmetica_n(nx):
nx=nx*r
return nx
print("value from n "+str(nx)

The function should multiply the value given (nx) and then print the result but it always print 0.0

Answer 1

Nope. It will just create an empty float object, aka 0.0. You could do nx = float(nx). But Taste 's approach is more elegant 👆

Answer 2

Line 5
Shouldnt it be nx=float(nx) ?

Answer 3

And why making a function without calling it?

Answer 4

First you define nx=str(input("Nx: ")). Then you redefine it as nx=float(). So whatever was entered before will be lost and nx will be overridden with 0.0 (the standard value of float()).

As already pointed out, the function aritmetica_n(nx) is never called so it won't do anything. Why are the lines nx=float() etc. indented?

Answer 5

Thanks!!

Answer 6

Sorry there is a last line of code:
print(aritmetica_n(nx))

Answer 7

Won't nx=float() transform nx into float??