Please write this program .. Ask the user to enter a list containing no's between 1&12 . Then replace all of the entries in the list that are greater then 10 with 10

Answer 1

Well, this is quite late, but in such an application, I suggest doing such modifications to the numbers before adding them to the list, to avoid the following iteration of the list.

Answer 2

liste=[]
for i in range(5):
num=int(input("Enter a number: "))
liste.append(num)
for i in liste:
if i>10:
liste[liste.index(i)]=10
print(liste)

this is for a list with 5 numbers, but feel free to make that number higher if you want to

Answer 3

Just started learning Python this week, but I still tried.
a = int(input('number1\n'))
b = int(input('number2\n'))
c = int(input('number3\n'))
d = int(input('number4\n'))
e = int(input('number5\n'))
f = int(input('number6\n'))
g = int(input('number7\n'))
h = int(input('number8\n'))
i = int(input('number9\n'))
j = int(input('number10\n'))
k = int(input('number11\n'))
l = int(input('number12\n'))
z = (a,b,c,d,e,f,g,h,i,j,k,l)
if 10 in z:
print ('10')
if 11 in z:
print ('10')
if 12 in z:
print ('10')
else:
print ('Error, please enter numbers from 1 to 12 only!')

Answer 4

Couldn't you remove the print line and pass the string as an argument to the input method? Another small thing is that he didn't request for printing.

Answer 5

How big should the list be?

Answer 6

The print was to demonstrate that you have to convert return value of map from iterable to list to print it. It would be fine to print iterables as well.

Answer 7

def replace(x):
if x > 10:
return 10
return x

len = int(input("Enter the number of elements in list"))
i = 0
l = []
while i < len:
l.append(float(input()))
i+=1

print(list(map(replace,l)))

Answer 8

What can you do with a list of "no's"?

Answer 9

no's = numbers. @Michael Timbes