Why is the size of union here 40?

Question

#include <stdio.h>
union uTemp{
double a;
int b[10];
char c;
}u;

int main() {
printf("%d\n",sizeof(u));
return 0;
}

Answer 1

Size of union = Size of largest data type.
Here the largest data type is array
int b[10]
whose size is 4x10 = 40 (size of int x number of elements)

Answer 2

We know that 4 is a int no and here it is give that int b[10] so the result is found 4×10=40 and 10 =size of array

Answer 3

40 bytes