Pointer in c. Why is the output = 41?

Question

#include <stdio.h>

int main() {
int *p=(int*)malloc(sizeof(int));
*p=42;
int* v=p;
*v=41;
printf("%d",*p);
free(p);
return 0;
}

Answer 1

You create a pointer v that points to the memory location of p, so when you change the value of the memory location that v points to, p will be changed accordingly

Answer 2

The values of pointers v and p are memory adresses. When v is assigned the value of p, they point on the same memory slot.

The preceeding asterix (*v = . .) means "write '...' into the memory slot v is pointing to". As p also points to the same slot (adress), eventually *p (reads like "the value at memory adress p") outputs that new value.

C is awesome! Happy coding :)

Edit: Anna, v does not 'point to the memory location of p' ( v != &p ), instead v points to the memory location p is also pointing to (you might want to clearify that in your answer). Saludos.