How to solve this

Question

i want to write a function using only a reduce or map that makes this :
>Myfunction(["a","b","c","d","e","f","g","h"])
["abc","bcd","cde","efg","fgh"]

It iterates three times ,when it arrives to the letter "g" it can't go farther since we cant concat three letters

HELP PLEASE , and than you .

Answer 1

Welcome. :)

Be sure not to just use the solution, but play around with it a bit so that you really understand and can use these tools yourself in the future!

Answer 2

Thank you so much ^^

Answer 3

Thank you HonFu you made my day !!!

Answer 4

Thank you Master 🙏🙏🙏🙏🙏🙏

Answer 5

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Answer 6

Can you use normal builtin tools? If yes, I'd do it like this:

s='abcdefg'
a=[]
i=0
while i<len(s)-3:
a.append(s[i:i+3])
i += 1
print(a)

If your letters come in a list, you can ''.join what you are going to append.

(And yeah, wrap a function around it if you like/need.)

Answer 7

No it's supposed to be a map or reduce otherwise its easy but thx anyway

Answer 8

But with map you will need some function.

Answer 9

What i know is that map function works this way :
map (lambda_function ,applay_to_list)
For example : we could have to scare elements on a list we apply a map this way :
map (lambda x : x**2, l)

Answer 10

It's more easier to write

Answer 11

You can use any function though, not only lambda. Is lambda a condition?

Answer 12

https://www.sololearn.com/learn/JUMP_LINK__&&__Python__&&__JUMP_LINK/2461/?ref=app

Answer 13

Here is what i mean by lambda

Answer 14

I understand, but syntaxwise you don't need to use lambda with map, you can use normal functions and methods too, like:

print(*map(str.upper, 'abcde'))

Answer 15

Oh okay i see , but how to fix this problem without using a loop or while ,only a map ? :/

Answer 16

You could try to design a recursive function. (Although there may be a simpler way... I don't use map very often. ^^')

Answer 17

A map is like a loop and should map my input which is :
["a","b","c","d","e","f","g","h"]
And should output only this :
["abc","bcd","cde","efg","fgh"]

Answer 18

A map is recursive no need to make a rec function

Answer 19

Is it? I thought map is iterative: It applies a function step by step on an iterable.

Answer 20

Would a tiny little zip be ok?

a=['a', 'b', 'c', 'd', 'e', 'f', 'g']
print(*map(lambda x: ''.join(x), zip(a, a[1:], a[2:])))